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6. A father's age is 3 times the sum of ages of his two sons. Five years later he will be twicethe sum of ages of his two sons. Find the present age of the father. |
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Answer» According to the question : → Father's age is 3 times of the sum of his two sons, and after 5 years he will be 2 times of the sum of age of his two sons . Let, → Age of two sons is "x" and "y" , according to the question , → Father's age is 3 times of sum of the ages of both , hence, → present age of father is 3(x + y) ....eq.(1) ,now also GIVEN that → after 5 years his age will be twice of the sum of them, therefore, → after 5 years ,age of father will be - 3(x + y)+ 5 , and ,age of sons be - x + 5 and y + 5 it will be twice of the sum of age of sons , → 3(x + y) + 5 = 2( x + 5 + y + 5 ) → 3x + 3y + 5 = 2x + 10 + 2y + 10 → 3x - 2x + 3y - 2x = 20 - 5 → x + y = 15 , hence ,from eq.(1) → Present age of father is → 3(x + y) → 3(15) → 45 , •°• Present age of father is 45 years |
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