1.

√6/√3-√2, Rationalise the denominators of the given numbers.

Answer» \bold{Answer :}

We multiply both the NUMERATOR and the DENOMINATOR of the given number by its CONJUGATE irrational number (√3 + √2) of its denominator.

Then,

(√6)/(√3 - √2)

= {(√6)(√3 + √2)}/{√3 + √2)(√3 - √2)}

= (3√2 + 2√3)/(3 - 2)

= (3√2 + 2√3)/1,

which is the required form.

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