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√6/√2+√3. Rationalize the denominatorPls help

Answer»

your QUESTION is:

\frac{ \sqrt{6} }{ \sqrt{2} +  \sqrt{3}  }

therefore the correct ANSWER will be

Step-by-step explanation:

\frac{ \sqrt{6} }{ \sqrt{2}   + \sqrt{ 3} }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

\frac{ \sqrt{6}( \sqrt{2}  -  \sqrt{3)}  }{ \sqrt{2 {}^{}}^{2}   -  \sqrt{3 {}^{2} } }

\frac{ \sqrt{12} -  \sqrt{18}  }{2 - 3}

\frac{ \sqrt{12}  -  \sqrt{18} }{ - 1}

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