.(6, 1), (8.2) and (9.4) are three vertices of a parallelogram taken i

1.	.(6, 1), (8.2) and (9.4) are three vertices of a parallelogram taken in order. Find the 4th vertex
Answer» Answer: SOLUTION : We know, diagonals of a PARALLELOGRAM bisects each other. It MEANS, Midpoint of AC = Midpoint of BD As, we have to find value of p, we will TAKE only X coordinates of AC and BD. 6+92=8+p2 ⇒15=8+p⇒p=7

.(6, 1), (8.2) and (9.4) are three vertices of a parallelogram taken in order. Find the 4th vertex

Answer»

Answer:

SOLUTION :

We know, diagonals of a PARALLELOGRAM bisects each other.

It MEANS,

Midpoint of AC = Midpoint of BD

As, we have to find value of p, we will TAKE only X coordinates of AC and BD.

6+92=8+p2

⇒15=8+p⇒p=7

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.(6, 1), (8.2) and (9.4) are three vertices of a parallelogram taken in order. Find the 4th vertex​

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.(6, 1), (8.2) and (9.4) are three vertices of a parallelogram taken in order. Find the 4th vertex