6. 1.7 ग्राम अमोनिया में उपस्थ

1.	6. 1.7 ग्राम अमोनिया में उपस्थित न्यूट्रॉनों की संख्या है - ''1JN(2) N/10 x4(3) (N,/10) x 7(4) N x 10 x7
Answer» In one atom of ammonia, Number of Electrons = 10 Number of Protons = 10 Number of NEUTRONS = Mass Number - ATOMIC Number = 17 - 10 = 7 Neutrons. Given--- Mass of Ammonia = 1.7 grams. MOLECULAR mass of Ammonia = 17 grams. Number of ATOMS = (Mass/Molecular mass) × Avogadro's Number(NA) = (1.7/17) × Avogadro's Number = 0.1 × Avogadro's Number = 0.1 Na ∵ one atom of Ammonia contains 7 Neutrons. ∴, 0.1 Na ---------------------------------- 7 × 0.1 Na = 0.7 Na = 0.7 × Na Since Na = 6.022 × 10²³ Thus, Number of Neutrons = 0.7 × 6.022 × 10²³ = 4.2154 × 10²³ Neutrons.

6. 1.7 ग्राम अमोनिया में उपस्थित न्यूट्रॉनों की संख्या है - ''1JN(2) N/10 x4(3) (N,/10) x 7(4) N x 10 x7

Answer»

In one atom of ammonia,

Number of Electrons = 10

Number of Protons = 10

Number of NEUTRONS = Mass Number - ATOMIC Number

= 17 - 10

= 7 Neutrons.

Given---

Mass of Ammonia = 1.7 grams.

MOLECULAR mass of Ammonia = 17 grams.

Number of ATOMS = (Mass/Molecular mass) × Avogadro's Number(NA)

= (1.7/17) × Avogadro's Number

= 0.1 × Avogadro's Number

= 0.1 Na

∵ one atom of Ammonia contains 7 Neutrons.

∴, 0.1 Na ---------------------------------- 7 × 0.1 Na

= 0.7 Na

= 0.7 × Na

Since Na = 6.022 × 10²³

Thus, Number of Neutrons = 0.7 × 6.022 × 10²³

= 4.2154 × 10²³ Neutrons.