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6.02×10*20 molecules of urea are present in 100ml solution.the concentration of urea solution is |
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Answer» Moles of urea = molecules/avogadro no = 6.02X10^20 / 6.022 X 10^23 = 10^-3 moles So it will have 10^-2 mole in 1 litre of solution because Molarity/concentration = mole / litre = 10^-3/1L = 10^-2M |
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