6.025*10^23 molecules of acetic acid are present in 500 ml of its solution the concentration of solution is

6.025*10^23 molecules of acetic acid are present in 500 ml of its solu

1.	6.025*10^23 molecules of acetic acid are present in 500 ml of its solution the concentration of solution is
Answer» ACTUALLY the concentration of solution is also CALLED molarity of that solution which is equal to no.of moles of solute DIVIDED by VOLUME of solution in LITRE.... so......no. of moles of solute =6.025×10(23)/6.025×10(23)...= 1 mole..... volume of solution =500 ml =0.5L so molarity or concentration = 1/0.5 = 2 molar...