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57. The standard deviation of 10, 16, 10, 16, 10, 10, 16, 16 is(a) 4(b) 6(c) 3.(d) o |
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Answer» ∑X = 10 + 16 + 10 + 16 + 10 + 10 + 16 + 16 = 104 ∑x^2 = 1424 so, x~ = 13 now find the value of summation of the square of given data,. ∑x^2 = (10)^2 + (16)^2 + (10)^2 + (16)^2 + (10)^2 + (10)^2 + (16)^2 + (16)^2 = 1424 so, we have ∑x^2 = 1424 n = 8 x~ = 13 SIGMA^2 = (1424/8) - (13)^2 calculate this we get, sigma = 3 option C is correct |
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