56. two gases a and b having same pressure P, volume v and temperature t are mixed. if mixture has volume v and temperature as vnt respectively OK, then pressure of mixture is

56. two gases a and b having same pressure P, volume v and temperature

1.	56. two gases a and b having same pressure P, volume v and temperature t are mixed. if mixture has volume v and temperature as vnt respectively OK, then pressure of mixture is
Answer» Explanation :Here, initally P Here, initally P 1Here, initally P 1 Here, initally P 1 = PHere, initally P 1 = PV Here, initally P 1 = PV 1Here, initally P 1 = PV 1 Here, initally P 1 = PV 1 =V+V = 2V;Here, initally P 1 = PV 1 =V+V = 2V;Finally, P Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VHere, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as INFERRED from equation)Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VHere, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 V Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 V 1Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 V 1VHere, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 V 1VP×2V Here, initally P 1 = PV 1 =V+V = 2V;Finally, P 2 = P; V 2 = VAS P 1 V 1 = P 2 V 2 (as inferred from equation)P 2 = VP 1 V 1VP×2V =2P

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56. two gases a and b having same pressure P, volume v and temperature t are mixed. if mixture has volume v and temperature as vnt respectively OK, then pressure of mixture is​

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56. two gases a and b having same pressure P, volume v and temperature t are mixed. if mixture has volume v and temperature as vnt respectively OK, then pressure of mixture is