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56. If ratio of sum of n terms of two AP is 14-4n:3n+5. Find tthe ratio of their 8terms. |
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Answer» n/2{2a1+(n-1)d1)/n/2{2a2+(n-1)d2}=14-4n/3n+5A1+(n-1)d1/2/A2+(n-1)D2/2=14-4n/3n+5now Nth term of an ap is given by a+(n-1)dnow (n-1)/2=N-1/2n=2N-1henceA1+(N-1)d1/A2+(N-1)d2=14-4(2N-1)/3(2N-1)put N=814-4(15)/3(15)=14-60/45=46/45 |
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