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55. A cyclist moving towards right with an acceleration of 4m/sec2.At t=0, he has travelled 5m moving towards the right at 15m/Sec.What will be his position at t=2 seconds?A.36B.38C.43​

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Answer:

Here is your answer

Explanation:

Suppose the acceleration is a then USING the second EQUATION of MOTION, s=ut+

2

1

at

2

and putting t=2sec and u=10m/s

we get 20=10×2+a×2

or a=0 that is UNIFORM motion



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