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54. A car starting from rest and moving along a straightpath with uniform acceleration covers distances pand q in the first two successive equal intervals oftime. Find the ratio of p to q.pearson foundation​

Answer»

<P>Answer:

p/q = 1/3

Explanation:

Given that CAR is starting from rest i.e u = 0

Consider the given time interval = t

Let the distance traveled in first interval of time is x₁

i.e p = x₁

Let the distance traveled in two time intervals is x₂

i.e q = x₂ - x₁.

Now, lets use the NEWTONS second equation of motion.

i.e s = ut + 1/2 at²

=> x₁ = 0 + 1/2 at²

=> p = 1/2 at².

Then,

x₂ = 0 + 1/2 a(2t)²

=> x₂ = 4/2 at²

=> x₂ = 2 at²

so, q = x₂ - x₁

=> q = 2 at² - 1/2 at²

=> q = 3/2 at².

Now, p/q = (1/2 at²)/(3/2 at²)

=> p/q = 1/3


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