1.

5111 5. + sin 3xe =lan 4x0055: + рео0532

Answer»

LHS = (sin5x + sin3x)/(cos5x + cos3x) use the formula, sinC + sinD = 2sin(C + D)/2.cos(C-D)/2 cosC + cosD = 2cos(C + D)/2.cos(C - D)/2

= {2sin(5x+3x)/2.cos(5x-3x)/2}/{2cos(5x+3x)/2.cos(5x-3x)/2}= (2sin4x.cosx)/(2cos4x.cosx)= sin4x/cos4x = tan4x = RHS



Discussion

No Comment Found