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51, 15 गी, 17 रो, मी लग्ये था 2 मी. 2 सेमी चौड़े फर्श परबिकने के लिये ग से । तिने वर्गाकार टाइल्सों कीजरूरत होगी।(a) 840 (b) 841(c) 820(d) 814. |
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Answer» please answer is 820 because he is a simple question Length of the room = 15 m 17 cm = 15 *100 +17 = 1517 cm.Breadth of the room = 9 m 2 cm = 902 cm.The HCF of the 1517 and 902 will be size of square tiles.HCF 1517 and 902 = 41 cm.Area of the room = length * breadth = 1517 * 902 cm2.Area of tiles = 41 *41 cm2 So, no. of tiles required = (1517 *902) /(41*41) = 814 tiles. |
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