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50ml of 0.2M NaOH + 50 ml 0.1M H2SO4 find ph |
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Answer» Hey, there! Here's the answer to the question. Normality = Molarity × n-factor. and number of equivalence = Normality × volume ➡️ n factor for NaOH is 1 and for H2SO4 is 2. (Now, refer to the attachment) Conclusion: Since, the number of equivalence of both acid and BASE is same, they completely react to form salt. For this, the solution becomes neutral, i.e., pH = 7 Hope that helps. Thanks. |
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