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50g of saturated solution of NaCl at 30 Cevaporated to dryness and 13.2g of dryCI was obtained. Find the solubility oflat 30°C in water. |
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Answer» Mass of water in solution = (50 – 13.2) = 36.8 g Solubility of NaCl = Mass of NaCl/Mass of water × 100 = 13.2/36.8 × 100=35.86 |
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