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500 mL of nitrogen at `27^(@)C` is cooled to `-5^(@)C` at the same pressure. The new volume becomesA. 326.32 mLB. 446.66 mLC. 546.32 mLD. 771.56 mL |
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Answer» Correct Answer - B Initial volume, `V_(1)=500" mL"` Initial temperature, `T_(1)=27^(@)C=27+273=300K` Final temperature, `T_(2)=-5+273=268K` `V_(2)=?` `(V_(1))/(T_(1))=(V_(2))/(T_(2))` `V_(2)=(V_(1)T_(2))/(T_(1))=(500xx268)/(300)` `=446.66" mL"` |
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