50 mL of a water sample consumed 15 mL of 0.01M EDTA before boiling and 5 mL of the same after boiling. 50 mL of the standard hard water (1000 mg/L) consumed 20 mL of EDTA. Calculate the degree of permanent, temporary and total hardness in terms of CaCO3 equiv.

50 mL of a water sample consumed 15 mL of 0.01M EDTA before boiling an

1.	50 mL of a water sample consumed 15 mL of 0.01M EDTA before boiling and 5 mL of the same after boiling. 50 mL of the standard hard water (1000 mg/L) consumed 20 mL of EDTA. Calculate the degree of permanent, temporary and total hardness in terms of CaCO3 equiv.
Answer» 50ML of water sample=15ml of 0.01M EDTA= ml of 0.01 EDTA=300ml of 0.01M EDTA=2300ml of 0.01 N EDTA=600 ml or 0.6 L of 0.01 eq. of CACO3=0.60.0150g CaCO3 eq.Then the total hardness=0.30g or 300mg of CaCO3 eq=300mg/L or ppmnow 50 ml of boiled water=5 ml of 0.01 M EDTA1000ml of boiled water= ml of 0.01 M EDTA=100 mL of 0.01 M EDTA=200ml or 0.2 L of 0.01 N EDTA=0.20.01*50 G of CaCO3 eq=0.1 g or 100MG of CaCO3 eqpermanent hardness=100mg/L or ppmTemporary hardness=300-100= 200ppm