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50 g of an alloy of gold and silver contains 80% gold (by weight). The quantity of gold, that is to be mixed up with this alloy, so that it may contain 95% gold is (a) 200 g (b) 150 g (c) 50 g (d) 10 g |
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Answer» (b) 150 g In 50 gm of an alloy of gold and silver, the quantity of gold = 40 gm and the quantity of silver = 10 gm, Let x gm of gold be mixed in 50 gm of an alloy of gold and silver such that quantity of gold becomes 95%. Then, 40 + x = 95% of (x + 50) 40 + x = \(\frac{19}{20}\)( x+ 50) \(\Rightarrow\) 800 + 20x = 19x + 950 \(\Rightarrow\) x = 150. |
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