1.

5.What is the value of (cos 67 -sin 23°)?

Answer»

Value of (cos^2 67 - sin^2 23)

We knowsin x = cos(90 - x)

Then we get, (cos^2 67 - sin^2 23)= (cos^2 67 - cos^2 (90 - 23)= (cos^2 67 - cos^2 67)= 0



Discussion

No Comment Found