5.Total vapour pressure of mixture of 1 mole of volatile component A (P^° A=100 mm Hg) and3 mole of volatile component B (P^° B=80 mm Hg) is 90 mm Hg. For such case: (1) there is positive deviation from Raoult's law (2) boiling point has been lowered (3) force of attraction between A and B is smaller than between A and A or between B and B (4) all the above statements are correct

5.Total vapour pressure of mixture of 1 mole of volatile component A (

1.	5.Total vapour pressure of mixture of 1 mole of volatile component A (P^° A=100 mm Hg) and3 mole of volatile component B (P^° B=80 mm Hg) is 90 mm Hg. For such case: (1) there is positive deviation from Raoult's law (2) boiling point has been lowered (3) force of attraction between A and B is smaller than between A and A or between B and B (4) all the above statements are correct
Answer» 5.Total vapour pressure of mixture of 1 mole of volatile component A (P^° A=100 mm Hg) and3 mole of volatile component B (P^° B=80 mm Hg) is 90 mm Hg. For such case: (1) there is positive deviation from Raoult's law (2) boiling point has been lowered (3) force of attraction between A and B is smaller than between A and A or between B and B (4) all the above statements are correct