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5) The maximum sheed ga trois ans po kmah It takes lohled to doucea distance of sookm. Find the cortion of awrage speed to maxsheed?​

Answer»

Question:-

A train goes from one STATION to another station with a normal speed. and comes back with double speed . if DISTANCE between the stations be 500 km . find the portion of AVERAGE speed to maximum speed.

Step-by-step explanation:

let normal speed of train be v km/ h

time taken to reach= distance/ speed

T1 = 500/ v

again

time taken to come back T2= 500/2v

average speed = total distance/ total time

= (500+500) / ( T1+T2)

= 1000/(T1+T2)

portion of maximum speed to average speed

2v/[ 1000 / (T1+T2)]

= [ 500/T2] / [ 1000/(T1+T2)]

=( 500/2T1) × [ ( T1+T2) / 1000]

= ( T1+T2) / 2T1

but in the question to find avg : Max

=>2 T1/ ( T1+T2)

but T2 = 2 T1=>

portion= 2T1/( T1+2T1)

ans = 2/3


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