(5*sin(theta) %2B 3*cos(theta))/(5*sin(theta) - 2*cos(theta))=7/2

1.	(5sin(theta) %2B 3cos(theta))/(5sin(theta) - 2cos(theta))=7/2
Answer» cotx=5/4; 5sinx+3 cosx/5sinx-2 cosx=7/2; 5(4/-3)+3(5/-3)/5(4/-3)-2(5/-3)=20+15/-3//20-10/-3=35/-3 x-10/-3=-350/-3=7/2=-3×7/350x2=21/700=3/10 7/2 is the correct answer of the given question 4cotA= 5cotA=5/4cosA/sinA=5/4cosA/5=sinA/4=k (let)cosA=4ksinA=4k5sinA+3cosA/5sinA-2cosA= 5×4k+3×4k/5×4k-2×5k20k+12k/20k-10k36k/10 sorry answer posted not complete so I am posting againcosA=5k sinA=4k5×4k+3×5k/5×4k-2×5k20k+15k/20k-10k35k/10k35/10=7/2 5 sinx+3 cosx / 5 sinx-2 cosx=5(4/3)+3(5/3)/5(4/3)-2(5/3)=20/3+15/3/20/3-10/3=35/3/10/3=35/10=7/2

(5sin(theta) %2B 3cos(theta))/(5sin(theta) - 2cos(theta))=7/2

Answer»

cotx=5/4; 5sinx+3 cosx/5sinx-2 cosx=7/2; 5(4/-3)+3(5/-3)/5(4/-3)-2(5/-3)=20+15/-3//20-10/-3=35/-3 x-10/-3=-350/-3=7/2=-3×7/350x2=21/700=3/10

7/2 is the correct answer of the given question

4cotA= 5cotA=5/4cosA/sinA=5/4cosA/5=sinA/4=k (let)cosA=4ksinA=4k5sinA+3cosA/5sinA-2cosA= 5×4k+3×4k/5×4k-2×5k20k+12k/20k-10k36k/10

sorry answer posted not complete so I am posting againcosA=5k sinA=4k5×4k+3×5k/5×4k-2×5k20k+15k/20k-10k35k/10k35/10=7/2

5 sinx+3 cosx / 5 sinx-2 cosx=5(4/3)+3(5/3)/5(4/3)-2(5/3)=20/3+15/3/20/3-10/3=35/3/10/3=35/10=7/2