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5. Show that 1/V2 +v3 -2/v5v3+3/v5-2-06. Find the value of th |
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Answer» (1/2+√3)+(2/√5-√3)+(1/2-√5)=1(2-√3)/(2-√3)(2+√3)+2(√5+√3)/(√5+√3)(√5-√3)+1(2+√5)/(2+√5)(2-√5)=(2-√3)/{2²-(√3)²}+2(√5+√3)/{(√5)²-(√3)²}+(2+√5)/{2²-(√5)²}=(2-√3)/(4-3)+2(√5+√3)/(5-3)+(2+√5)/(4-5)=2-√3+{2(√5+√3)/2}-(2+√5)=2-√3+√5+√3-2-√5=0 (Proved) |
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