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5 mole of an ideal gas at constant external pressure of 1.5 bar are expanded from 20 dm3 amount of work done is -700J calculate it's final volume. |
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Answer» We have given, Constant external pressure = 1.5 bar or 1.5 x 105 Pa or 1.5 x 105 N m-2 Initial volume of gas = 20dm3 or 0.020m3 Workdone = -700 J W = \(\int\limits_{V_1}^{V_2} \)- Pextd V W = -Pext \(\int\limits_{V_1}^{V_2} \)d V W = -Pext x(V2 -V1) -700 J = - 1.5 X 105 ( V2 - 0.0.02 m3) = 700/1.5 x 105 = V2-0.02 = 0.00467 = V2 - 0.002 = V2 = 0.00467 + 0.020 V2 = 0.02467 m3 or V2 = 24.67 dm3 |
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