5 litre of N2 under a pressure of 2 atm, 2 litre of O2 at 5.5 atm and 3 litres of CO2 at 5 atm are mixed the resultant volume of the mixture is 15 litres calculate the partial pressure of each constituent

5 litre of N2 under a pressure of 2 atm, 2 litre of O2 at 5.5 atm and

1.	5 litre of N2 under a pressure of 2 atm, 2 litre of O2 at 5.5 atm and 3 litres of CO2 at 5 atm are mixed the resultant volume of the mixture is 15 litres calculate the partial pressure of each constituent
Answer» Explanation: artial pressure of N2 =Vol of N2 ×pressure of N2Total volume =5×215 =0.66 atmPartial pressure of N2 =Vol of N2 ×pressure of N2Total volume =5×215 =0.66 ATM[As P1V1 = P2V2, P1= P2V2/V1 , Boyle's LAW] Partial pressure of O2 =Vol of O2 ×pressure of O2Total volume =2×5.515 =0.73 atmPartial pressure of O2 =Vol of O2 ×pressure of O2Total volume =2×5.515 =0.73 atm Partial pressure of CO2 =Vol of CO2 ×pressure of CO2Total volume =3×515 =1 atmPartial pressure of CO2 =Vol of CO2 ×pressure of CO2Total volume =3×515 =1 atm Thus TOTAL partial pressure = 0.33+0.73+1 atm =2.06 atm