5. In figure 3.85, ABCD isa1S aparallelogram. It circumscribes thecirc

1.	5. In figure 3.85, ABCD isa1S aparallelogram. It circumscribes thecircle with cnetre T. Point E,F, G, Hare touching points. IfAE-4.5,EB = 5.5, find AD
Answer» We know that the parallelogram circumscribing a circle is a Rhombus . ABCD is a parallelogram circumscribing a circle with center T . AE = 4.5 , EB = 5.5 ( Given ) Therefore , ABCD is a Rhombus . AB = BC = CD = DA AD = AB = AE + EB = 4.5 + 5.5 = 10

5. In figure 3.85, ABCD isa1S aparallelogram. It circumscribes thecircle with cnetre T. Point E,F, G, Hare touching points. IfAE-4.5,EB = 5.5, find AD

Answer»

We know that the parallelogram circumscribing a

circle is a Rhombus .

ABCD is a parallelogram circumscribing

a circle with center T .

AE = 4.5 ,

EB = 5.5 ( Given )

Therefore , ABCD is a Rhombus .

AB = BC = CD = DA

AD = AB

= AE + EB

= 4.5 + 5.5

= 10