5. gcd (2015! + 1, 2016! + 1) =?(n! = n*(n-1)*(n-2)..... 3*2*1)Or 6! = – InterviewSolution

1.

5. gcd (2015! + 1, 2016! + 1) =?(n! = n(n-1)(n-2)..... 321)Or 6! = 654*321 = 720

Answer»

Answer is in the ATTACHMENT

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