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5. Find the sum of first 16 terms of A.P. 10, 6, 2....ha |
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Answer» sn=n/2(2a+(n-1)d)n=16,a=10,d=-4s16=16/2(2(10)+(16-1)-4)s16=8(20-60)s16=8(-40)s16=-320 |
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