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5. Calculate the compound interest for the second year on 6000 invested for 3 years at10% p.a. Also find the sum due at the end of thirdyear. |
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Answer» COMPOUND Interest=p(1+R/100)^n 6000(1+10/100)^1 6000×11/10 600×11=6600 6600 for second year At the end of THIRD year 6000(11/10)^3 6×1331=7986 sum due=7986-6600=1386 PLEASE MARK ME AS BRAINLIEST AND FOLLOW ME |
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