1.

5. Calculate the compound interest for the second year on 6000 invested for 3 years at10% p.a. Also find the sum due at the end of thirdyear.​

Answer»

ANSWER:

COMPOUND Interest=p(1+R/100)^n

6000(1+10/100)^1

6000×11/10

600×11=6600

6600 for second year

At the end of THIRD year

6000(11/10)^3

6×1331=7986

sum due=7986-6600=1386

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