1.

5 and 6 hours(0) +0 uuu18. Pipes A and B can fill a tank in 5 and 6respectively. Pipe C can empty it in 12 hoursThe tank is half full. All the three pipes areoperation simultaneously. After how much timewill the tank will be full.​

Answer»

Use harmonic MEAN to solve this type of QUESTIONS,,
To FILL or EMPTY it is same. therefore when three pipes fill the tank simultaneously, it takes 3/[(1/a)+(1/b)+(1/c)]
=>3/[(1/5)+(1/6)+(1/12)]=3/[(12+10+5)/60]
=>3*60/27=60/9=20/3=6.66,, we REQUIRED half tank to fill, therefore 20/6=3.333 or 6.66/2=3.333. Therefore it takes 3.33hours!!



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