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5. A force of 500 N acts on the surface of area 0.3 cm normally. What would be the thrust and pressure on the surface?​

Answer»

pressure = F/A (force per unit area)F= 500nA= 0.3cm2 = 0.3/100×100 = 0.03p=FA• 1200×0.03• 36 n/m2 = pa (pa means Pascals)Hope it will HELP you Explanation:MARK ME AS BRAINLIST



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