Saved Bookmarks
| 1. |
5. A force of 500 N acts on the surface of area 0.3 cm normally. What would be the thrust and pressure on the surface? |
|
Answer» pressure = F/A (force per unit area)F= 500nA= 0.3cm2 = 0.3/100×100 = 0.03p=FA• 1200×0.03• 36 n/m2 = pa (pa means Pascals)Hope it will HELP you Explanation:MARK ME AS BRAINLIST |
|