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5 90°Find the roots of quadratic equation 2x2 -7x+3=0by the method of completing the square. |
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Answer» 2x^2 - 7x + 3 = 02x^2 - 7x = -3X^2 - 7x/2 = -3/2X^2 - 2*1/2*7x/2 = -3/2X^2 - 2*1/2*7x/2 + (7/4)^2 = -3/2 + (7/4)^2(X - 7/4)^2 = -3/2 + 49/16(X - 7/4)^2 = 25/16X - 7/4 = + or -5/4 x = +5/4 + 7/4X = 12/4 =3Also X = -5/4 + 7/4 = 1/2Hence x = 3 and 1/2 |
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