5 9 Coo+ 40SinA =Ml TG (0S4 Wiz Losee”) oआना दा करे

1.	5 9 Coo+ 40SinA =Ml TG (0S4 Wiz Losee”) oआना दा करे N 6N3/
Answer» i) Dividing both sides by 41, (9/41)cos(A) + (40/41)sin(A) = 1 ii) This is of the form, cos(A)cos(B) + sin(A)sin(B) = 1, where cos(B) = 9/41 and sin(B) = 40/41 iii) So, cos(A - B) = 1==> A - B = 2nπHence A = 2nπ + B iv) So, cos(A) = cos(2nπ + B) = cos(B) = 9/41csc(A) = csc(2nπ + B) = csc(B) = 41/40 Like my answer if you find it useful!

5 9 Coo+ 40SinA =Ml TG (0S4 Wiz Losee”) oआना दा करे N 6N3/

Answer»

i) Dividing both sides by 41, (9/41)*cos(A) + (40/41)*sin(A) = 1

ii) This is of the form, cos(A)*cos(B) + sin(A)*sin(B) = 1, where cos(B) = 9/41 and sin(B) = 40/41

iii) So, cos(A - B) = 1==> A - B = 2nπHence A = 2nπ + B

iv) So, cos(A) = cos(2nπ + B) = cos(B) = 9/41csc(A) = csc(2nπ + B) = csc(B) = 41/40

Like my answer if you find it useful!