5.6l of methane gas is ignited in oxygen gas. Calcate the number of mo

1.	5.6l of methane gas is ignited in oxygen gas. Calcate the number of moles of carbondioxide formed?
Answer» ANSWER: Explanation: CH4 + 2O2 = CO2 + 2H20 No.of MOL of CH4 = 5.6/22.4 = 0.25 mol According to the stoichiometry of the reaction 1 mol of CH4 = 1 mol of CO2 Hence, 0.25 mol of CH4 = 0.25 mol of CO2

5.6l of methane gas is ignited in oxygen gas. Calcate the number of moles of carbondioxide formed?

Answer»

Explanation:

CH4 + 2O2 = CO2 + 2H20

No.of MOL of CH4 = 5.6/22.4 = 0.25 mol

According to the stoichiometry of the reaction

1 mol of CH4 = 1 mol of CO2

Hence, 0.25 mol of CH4 = 0.25 mol of CO2