1.

4x^2-4ax+(a^2-b^2)=0​

Answer» ONG>Step-by-step EXPLANATION:

2The given quadratic equation is 4x

2

−4ax+(a

2

−b

2

)=0

4x

2

−4ax+(a+b)(a−b)=0

⇒4x

2

+[−2a−2a+2b−2b]X+(a−b)(a+b)=0

⇒4x

2

+(2b−2a)x−(2a+2b)x+(a−b)(a+b)=0

⇒4x

2

+2(b−a)x−2(a+b)x+(a−b)(a+b)=0

⇒2x[2x−(a−b)]−(a+b)[2x−(a−b)]=0

⇒[2x−(a−b)][2x−(a+b)]=0

⇒2x−(a−b)=0,2x−(a+b)=0

⇒x=

2

a+b

,

2

a-b .2ab ,

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