46 gm of ethyl alcohol is dissolved in 18gm of water . Calculate the m

1.	46 gm of ethyl alcohol is dissolved in 18gm of water . Calculate the molefraction of ethyl alcohol.
Answer» Given:- →Mass of ethyl alcohol (solute) = 46g →Mass of WATER (SOLVENT) = 18g To find:- →MOLE fraction of ethyl alcohol Solution:- •Chemical formula of ethyl alcohol = C₂H₅OH •Chemical formula of water = H₂O Molar mass of ethyl alcohol :- = 12×2+1×5+16+1 = 24+5+17 = 46g Molar mass of water :- = 1×2+16 = 18g NUMBER of moles in 46g of ethyl alcohol:- = Given Mass/Molar mass = 46/46 = 1 mole Number of moles in 18g of water:- = 18/18 = 1 mole Mole fraction:- = Moles of solute/Total moles in solution = 1+/(1+1) = 1/2 = 0.5 Thus, the mole fraction of ethyl alcohol is 0.5.

46 gm of ethyl alcohol is dissolved in 18gm of water . Calculate the molefraction of ethyl alcohol.

Answer»

→Mass of ethyl alcohol (solute) = 46g

→Mass of WATER (SOLVENT) = 18g

→MOLE fraction of ethyl alcohol

•Chemical formula of ethyl

alcohol = C₂H₅OH

•Chemical formula of water = H₂O

Molar mass of ethyl alcohol :-

= 12×2+1×5+16+1

= 24+5+17

= 46g

Molar mass of water :-

= 1×2+16

= 18g

NUMBER of moles in 46g of ethyl alcohol:-

= Given Mass/Molar mass

= 46/46

= 1 mole

Number of moles in 18g of water:-

= 18/18

= 1 mole

Mole fraction:-

= Moles of solute/Total moles in

solution

= 1+/(1+1)

= 1/2

= 0.5

Thus, the mole fraction of ethyl alcohol is 0.5.