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450cm3 of nitrogen monoxide and 200cm³ of oxygen are mixed together and ignited.Calcilate the composition of resulting mixture |
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Answer» Hello friend...!! It is given that, 2NO (g) + O2 (g) -------> 2NO2(g)2vol : 1 VOL ------> 2vol ( according to LUSSAC's law) •To calculate amount of unused NO NO : O22 : 1 X : 200 Implies X = 400 cm^3.Total given nitrogen monoxide is 450 THEREFORE 450 - 400 = 50cm^3.• To calculate amount of NO2 FORMED :O2 : NO2 1 : 2 200 : X1Implies X1 = 400cm^3.Therefore unused NO = 50cm^3 and amount of NO2 formed = 400cm^3Therefore the total mixture composition is 450 cm^3.--------------------------------------------Hope it is useful...!! Read more on Brainly.in - brainly.in/question/3262310#readmore |
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