450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together

1.	450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited . calculate the composition of resulting mixture .
Answer» Hello beautiful..!! It is given that, 2NO (g) + O2 (g) -------> 2NO2(g) 2vol : 1 vol ------> 2vol ( according to lussac's law) •To CALCULATE amount of unused NO NO : O2 2 : 1 X : 200 IMPLIES X = 400 cm^3. TOTAL given nitrogen monoxide is 450 therefore 450 - 400 = 50cm^3. • To calculate amount of NO2 formed : O2 : NO2 1 : 2 200 : X1 Implies X1 = 400cm^3. Therefore unused NO = 50cm^3 and amount of NO2 formed = 400cm^3 Therefore the total mixture composition is 450 cm^3. -------------------------------------------- Hope it is useful...!!

450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited . calculate the composition of resulting mixture .

Answer»

Hello beautiful..!!

It is given that,

2NO (g) + O2 (g) -------> 2NO2(g)

2vol : 1 vol ------> 2vol ( according to lussac's law)

•To CALCULATE amount of unused NO

NO : O2

2 : 1

X : 200

IMPLIES X = 400 cm^3.

TOTAL given nitrogen monoxide is 450 therefore 450 - 400 = 50cm^3.

• To calculate amount of NO2 formed :

O2 : NO2

1 : 2

200 : X1

Implies X1 = 400cm^3.

Therefore unused NO = 50cm^3 and amount of NO2 formed = 400cm^3

Therefore the total mixture composition is 450 cm^3.

--------------------------------------------

Hope it is useful...!!