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45. A parallel plate capacitor consists of two circular metal plates, each of radius \( 1.38 cm \). A coating of Teflon \( 40 \mu m \) thick is applied to the inner surface of one plate to provide a dielectric layer, and then the plates are pressed together. Find the voltage to be applied between the plates of this capacitor to establish a charge of \( 0.5 nC \) on each plate. (Given: \( \varepsilon_{0}=8.854 \times 10^{-12} F / m \) and dielectric constant of Teflon \( =2 \) ). |
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Answer» Answer: Given: r= 1.38 x 10-2 m D= 40x10-6 m Q=0.5x10-9 C Area= πr2 = ~6x10-4 m2 C = KE0A/D = 2 x 8.8 x 10-12 x 6 x 10-4 /40 x 10-6 = 0.25 x 10-9F V=Q/C. = 0.5 x 10-9/0.25 x 10-9 = ~2v We get 2 Volts as the answer buy the perfect answer is 1.92 volts as the value of C was taken as .25 but might come as .26 for some people but 2V can be considered as the answer. |
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