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44. If a man travels at a speed of 30 km/hr, hereaches his destination 10 minutes late and ifhe travels at a speed of 42 km/hr, he reacheshis destination 10 minutes early. The distancetravelled is : |
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Answer» Let.....x be required distance.x/s=t...........nowby 1 st condition...x/30=t+1/15...................................( 4 minutes=1/15 hours)and by second equationx/30=t-1/6from above equations,x/25 -1/15=x/30 +1/6sox=35 kmans is 35 km Let the distance be x km. Then, correct time at a speed of 30 km / h =x30x30-10601060 Correct time at a speed of 42 km /h =x42x42+10601060 =>x30x30-10601060=x42x42+10601060 =>x30x30-x42x42=2626 =>x(12)1260x(12)1260=2626 => 72 x = 1260××2 => x =1260×2721260×272=> x = 35 km |
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