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44. Consider a uniform electric field E = 3x10î N/C. What is the flux of this field through a square of 10 cm on a sidewhose plane is parallel to the y- z plane?(b) 20 NC- m?(d) 40 NC-1 m(a) 10 NC-'m(c) 30 NC-'m |
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Answer» (c) 30 NC-'mexplanation: (a) Electric field intensity, E =3×10^3 N/CMagnitude of electric field intensity, ∣E∣=3×10^3 N/CSide of the square, s=10cm=0.1mArea of the square, A=s^2 =0.01m^2 The PLANE of the square is parallel to the y-z plane. Hence, ANGLE between the UNIT vector normal to the plane and electric field, θ=0° Flux (ϕ) through the plane is given by the relation,ϕ=∣E∣Acosθ =3×10^3 ×0.01×cos0°=30Nm^2 /C(B)Plane makes an angle of 60° with the x-axis. Hence, θ=60° Flux, ϕ=∣E ∣Acosθ =3×10^3×0.01×cos60° =30×1/2 =15Nm^2/C |
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