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43 H-C=--H(ethylene) + naoh = H-C=-CNa + h2o For the above reaction the K equilibrium is A. K>1 B. K

Answer» 43 H-C=--H(ethylene) + naoh = H-C=-CNa + h2o For the above reaction the K equilibrium is A. K>1 B. K<1 C. K=1 D. K=0


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