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40g of benzene and 50g of toluene are added to prepare a solution.find the mole fraction of each component? |
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Answer» the total mass of the solution be 100 g and the mass of benzene be 30 g.∴ Mass of carbon tetrachloride = (100 - 30)g = 70 gMolar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g MOL - 1= 78 g mol - 1∴ NUMBER of moles of C6H6 =30/78 mol= 0.3846 molMolar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 35.5= 154 g mol - 1∴ Number of moles of CCl4 = 70/154 mol= 0.4545 molThus, the MOLE fraction of C6H6 is GIVEN as:= 0.3846 / (0.3846 +0.4545)= 0.458 |
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