40. A ABC is an isosceles triangle. AB = AC and AD is the median.i) Pr

1.	40. A ABC is an isosceles triangle. AB = AC and AD is the median.i) Prove that A ADB = A ADC.ii) Is ZBAD = _ CAD? Why?
Answer» Correct OPTION is D 55 ABC is an isosceles triangle SINCE AB=AC. ∠B=∠C=35 ∘ ∠A=110 ∘ (∵∠A+∠B+∠C=180 ∘ ) In an isosceles triangle, MEDIAN (AD) to the base BC is the angular BISECTOR of ∠A Hence, ∠BAD=55 ∘

40. A ABC is an isosceles triangle. AB = AC and AD is the median.i) Prove that A ADB = A ADC.ii) Is ZBAD = _ CAD? Why?

Answer»

Correct OPTION is

ABC is an isosceles triangle SINCE AB=AC. ∠B=∠C=35

∘

∠A=110

∘

(∵∠A+∠B+∠C=180

∘

)

In an isosceles triangle, MEDIAN (AD) to the base BC is the angular BISECTOR of ∠A

Hence, ∠BAD=55

∘

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40. A ABC is an isosceles triangle. AB = AC and AD is the median.i) Prove that A ADB = A ADC.ii) Is ZBAD = _ CAD? Why?

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