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40. A ABC is an isosceles triangle. AB = AC and AD is the median. i) Prove that A ADB = A ADC. ii) Is ZBAD = _ CAD? Why?

Answer» RECT option is

D

55

ABC is an isosceles triangle since AB=AC. ∠B=∠C=35

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∠A=110

∘

(∵∠A+∠B+∠C=180

∘

)

In an isosceles triangle, median (AD) to the BASE BC is the ANGULAR bisector of ∠A

Hence, ∠BAD=55

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