1.

4 years ago meera was 3 times as old as manu.8years later Meera would be twice as old as Manu. How old are they now?​

Answer»

Step-by-step explanation:

\bf{\underline{\underline\red{Given:-}}}

  • 8 years later Meera WOULD be twice as old as Manu.

\bf{\underline{\underline\blue{To\:Find:-}}}

  • The present ages of Manu and Meera.

\bf{\underline{\underline\green{Solution:-}}}

Let the present age of Meera = x

And present age of Manu be y

4 years ago:-

Age of Meera = (x - 4)

Age of Manu = (y - 4)

Meera is 3 times as old as Manu

→ x - 4 = 3(y - 4)

→ x - 4 = 3Y - 12

→ x - 3y = -12 + 4

→ x - 3y = -8.......(i)

8 years later:-

Age of Meera = (x + 8)

Age of Manu = (y + 8)

Meera will be twice as old as Manu

→ x + 8 = 2(y + 8)

→ x + 8 = 2Y + 16

→ x - 2y = 16 - 8

→ x - 2y = 8

→ -( x -2y = 8)

→ -x + 2y = -8.......(ii)

Adding equation (i) and (ii)

\: \: \: \rm \not x - 3y = - 8

\rm -\not x + 2y = - 8

_____________

→ -3y + 2y = -8 - 8

→ -y = -16

→ y = 16

Substituting y = 16 in equation (i)

→ x - 3y = -8

→ x -3(16) = -8

→ x - 48 = -8

→ x = -8 + 48

→ x = 40

Present age of Meera = x = 40 years

Present age of Manu = y = 16 years


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