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\( 4 x+\frac{y}{3}=\frac{8}{3} ; \frac{x}{2}+\frac{y}{4}=\frac{-5}{2} \) |
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Answer» \(4x +\frac{y}{3} =\frac {8}{3}\) ⇒ 12 x + y = 8 — (1) ( on multiplying both sides by 3) and \(\frac{x}{2}+\frac{y}{4}=-\frac{5}{2}\) ⇒ 2x + y = -10 — (2) ( on multiplying both sides by 4) subtract equation (2) from (1) , we get (12x+y) - (2x+y) = 8 - (-10) ⇒ 10x = 18 ⇒ x = \(\frac{18}{10}=\frac{9}{5}\) ∴ from (2), we obtain \(\frac{18}{5}+y=-10\) ⇒ y = -10 - \(\frac{18}{5}\) = \(\frac{−50−18}{5}=\frac{−68}{5}\) |
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