4. The sum of a two-digit number and the numberobtained by reversing i

1.	4. The sum of a two-digit number and the numberobtained by reversing its digits in 121. Find thenumber, if its units place digit is greater thanthe tens place digit by 7.
Answer» ≡QUESTION≡ The sum of a two-digit number and the number obtained by reversing its digits in 121. FIND the number, if its units place digit is greater than the tens place digit by 7. ║⊕ANSWER⊕║ Let the tens digit be X Let the ones digit be y The original no = 10 x + y The REVERSED no: is = 10 y + x According to the question 10x + y + 10y + x =1 21 11x + 11y = 121 x + y = 11 x+ x + 7=11 [∵ the units digit is 7 more than the tens digit] 2x = 4 x = 2 y= 11-2 =9 ∴ The required number is 29

4. The sum of a two-digit number and the numberobtained by reversing its digits in 121. Find thenumber, if its units place digit is greater thanthe tens place digit by 7.

Answer»

≡QUESTION≡

The sum of a two-digit number and the number obtained by reversing its digits in 121. FIND the number, if its units place digit is greater than the tens place digit by 7.

║⊕ANSWER⊕║

Let the tens digit be X

Let the ones digit be y

The original no = 10 x + y

The REVERSED no: is = 10 y + x

According to the question

10x + y + 10y + x =1 21

11x + 11y = 121

x + y = 11

x+ x + 7=11

[∵ the units digit is 7 more than the tens digit]

2x = 4

x = 2

y= 11-2

∴ The required number is 29

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4. The sum of a two-digit number and the numberobtained by reversing its digits in 121. Find thenumber, if its units place digit is greater thanthe tens place digit by 7.​