Saved Bookmarks
| 1. |
4. The solution set ofx +1+ 6 = 0 is :x +1)COINNICONICO |
|
Answer» (x / x+ 1)^2-5(x/ x+1) + 6 =0; ( x^2 / x^2+2(x)( x+1))-5x / x+1+6 = = ( x^2/ x^2 + 2x^2+x)-5x/x +7 =(x^2/3x^2+x - 5x / x+7)= =( x^2/3x^2+x -5x/ x+7)+6=0 = x^2( x+7)-5x(3x^2+x)+6= x^3 +7x^2 - 15x^3+5x^2 +6= -14x^3+12x^2+6=2(-7x^3+6x^2+3) = (-2, 3/2) Let x/(x+1) be y.Therefore,y^2-5y+6=0y^2-2y-3y+6=0y(y-2)-3(y-2)=0(y-2)(y-3)=0Therefore,y=2 or y =3.Putting the value of y,x/(x+1)=2x=2x+2x=-2.x/(x+1)=3x=3x+3.-2x=3.x=-3/2. |
|